Question

a solid round bar 4m long and 6cm in diameter is used as strut with both ends hinged. determine the crippling load. take E=2×10^5 N/mm^2​

Answer 1

Answer:

Step 1: Data

Length of the column = 2500mm

Diameter of the column = 60mm

Condition = one end hinged and other end fixed

Crippling load =??

FOS=3.5

E=2.1x105N/mm2

Step 2: Calculation of moment of inertia

I = π d 4 / 64

I= π (60)4 / 64

I = 0.636X106mm4

Step 3: Calculation of crippling load

Condition = one end hinged and other end fixed

P = 2 Π 2E I/ L2

P = 2 Π 2(2.1x105) (0.636X106) / (2500)2

P = 421.81 KN

Step 4: Calculation of safe load

Safe load = crippling load /FOS

Safe load = 421.81/3.5

Safe load = 120.52KN

Explanation:

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