Question

A solid round of baron 3.5m long and 50mm diameter is used as a column with bends are hinges. Determine crippling load, take E=2*10^5 N/mm^2

Answer 1

Answer:

Crippling Load (Pb) = 49.36 KN

Explanation:

Given,

Bends are Hinges . Therefore Le=L

Le=3.5m=3500 mm

d=50mm

E=2*10^5 N/mm^2

Imin=(pi/64)*d^4

       = (3.14/64)*(50)^4

       = 306,640.625 mm^4

we know that

Pb=[(Pi^2)*E*Imin]/Le^2

    = [(3.14*3.14)*2*10^5*306,640.5]/(3500*3500)

    =(604,670,534,760)/(12,250,000)

    = 49,360.85 N

    = 49.36 KN

Answer 2

Answer:

pb=49.36 kn

Explanation:

Hope it helps you