Question

A solid shaft of 20 mm radius is transmitting 2.5 kW with the frequency of 50 Hz.
Calculate the maximum shear stress.


(A) Tmax=1.266 MPa
(B) Tmax = 0.633 MPa
(C) Tmax=1.899 MPa
(D) Tmax=0.9495 MPa​

Answer 1

Answer:

Shear stress is given by -

Shear stress = 2τ / πr³

Shear stress = 2 (P/2πf) / πr³

Shear stress = P / π²r³f

Substitute values,

Shear stress = 2.5×10^3 / (3.14^2 × 0.01^3 × 50)

Shear stress = 5.071×10^6 Pa

Explanation:

Answer -

Shear stress = 5.071×10^6 Pa

● Explanation -

# Given -

r = 20/2 = 10 mm = 0.01 m

P = 2.5 kW = 2.5×10^3 W

f = 50 Hz