Question

A solid sphere 6 cm.in diameter is formed into a tube 10 cm. in external diameter and 4 cm.in length. Find the thickness of the tube.

Answer 1

volume of sphere=4/3πr^3=4/3*π*3*3*3
volume of cylinder=volume of sphere
4/3×π×3*3*3*=π×r^2×4
r^2=9
r=3

thickness=external radius- internal radius
thickness=5-3
thickness=2cm

Answer 2

Answer:

1cm

Step-by-step explanation:

let R - External Radius of tube

r= Internal radius

h= length of tube

k= radius of sphere

now ATQ :

volume of hollow cylinder = volume of solid sphere

πh(R² - r²) = 4/3 π k³

h(R² - r²) = 4/3 k³

4(5² - r²) = 4/3 x 3x3x3 (bcoz h=4, R=5 , k =3)

25-r² = 9

r² = 25-9 =16

r = 4 cm

now thickness = External radius - internal radius

=R-r = 5-4 = 1 cm ☺️