A solid sphere, a hollow sphere and a disc, all having same mass and radius, are placed at the top of an incline and released. The friction coefficients between the objects and the incline are same and not sufficient to allow pure rolling. Least time will be taken in reaching the bottom by
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least k2/r2 value jiska hoga vo pahale pahuchega
solid sphere ka 2/5
hollow sphere ka 2/3
disc ka 1/2
solid sphere ka 2/5
hollow sphere ka 2/3
disc ka 1/2
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- Use:
time taken= (1/ sin theta) . root of {( 2h/g) (1+ k^2/r^2) }
Every objects given in the question have the same above formula but (k^2/r^2) are different..
1. For solid sphere
(k^2/r^2)= 2/5
2. For hollow sphere
(k^2/r^2)= 2/3
3.For disc
(k^2/r^2)=1/2
FOR FURTHER KNOWLEDGE, SEE IN THE ATTACHMENT.. YOU GET TO KNOW SOME MORE INFO ABOUT THE VALUES RELATED TO THIS QUESTION...
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