A solid sphere and a solid cylinder of same mass
rolled down on two inclined planes of heights h1 and
h2 respectively. If at the bottom of the plane the two
objects have same linear velocities, then the ratio of
h1: h2 is
(a) 2:3
(b) 7:5
(c) 14:15
(d) 15:14
Answers
Answered by
2
Answer:
the answer is {d} - 15:14
Answered by
5
The ratio of h1 : h2 is 14 : 15
Explanation:
From question, the mass and linear velocity of solid sphere and a solid cylinder is same.
Thus, the kinetic energy of solid sphere and a solid cylinder is same.
(KT)sphere = (KT)cylinder
(5/7 × mgh1) = (2/3 × mgh2)
(5/7 × h1) = (2/3 × h2)
h1/h2 = 2/3 × 7/5
∴ h1/h2 = 14/15
Similar questions