A solid sphere has a radius of 2cm and mass 0.05kg.what is the relative density of sphere
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Answered by
1
Volume of sphere = 4πr³/3
= 4 × 3.14 × (2 cm)³ / 3
= 33.5 cm³
Density = Mass / Volume
= 50 g / 33.5 cm³
= 1.5 g/cm³
Relative denisty = Density of substance / Density of water
= (1.5 g/cm³) / (1 g/cm³)
= 1.5
∴ Relative Density of sphere is 1.5
= 4 × 3.14 × (2 cm)³ / 3
= 33.5 cm³
Density = Mass / Volume
= 50 g / 33.5 cm³
= 1.5 g/cm³
Relative denisty = Density of substance / Density of water
= (1.5 g/cm³) / (1 g/cm³)
= 1.5
∴ Relative Density of sphere is 1.5
Answered by
28
Answer:
Radius of sphere=2cm =2/100=0.02 m
Volume of the sphere=4/3
.
r³
=4/3× 22/7×0.02×0.02m³=0.000704/21 m³
Mass of sphere=0.05kg.
Relative density of sphere=density ×10³
=0.05/0.000704\21 ×10
=0.05×21/704×10-6×10³
=1.05×10³/704×10-6
=1.05×10³±6/704=1.05×109/704=1.49×106
Relative density of sphere= 1.49×106 kg/m³
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