Question

A solid sphere of diameter 24cm is melted and recast into spherical balls of 2cm diameter. find the number of such balls made

Answer 1

Hi friend ✋✋✋✋
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Your answer
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Diameter of a solid sphere = 24 cm

Radius of the sphere = 24/2 cm = 12 cm

The sphere is melted and recasted into smaller spherical balls.

Diameter of the smaller balls = 2 cm

Radius of the smaller balls = 2/2 cm = 1 cm

So,
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Number of such baks that can be made = (4/3 × π × 12 × 12 × 12 )/(4/3 × π × 1 × 1 × 1)
= 1728 balls

HOPE IT HELPS

Answer 2

hiii!!!

here's ur answer...

$givem \: the \: diameter \: of \: the \: spherical \: \\ ball \: is \: 24cm. \\ \\ therefore \: radius \: of \: the \: spherical \: ball \\ = \frac{24}{2} = 12cm \\ \\ volume \: of \: spherical \: ball \: = \frac{1}{3}\pi {r}^{3} \\ \\ = \frac{1}{3} \times \frac{22}{7} \times {12}^{3} \\ \\ = \frac{1}{3} \times \frac{22}{7} \times 12 \times 12 \times 12 \\ \\ = \frac{22}{7} \times 4 \times 12 \times 12 \\ \\ = \frac{12672}{7} {cm}^{3} \\ \\ diameter \: of \: the \: small \: ball \: = 2cm \\ \\ radius \: is \: = \frac{2}{2} = 1cm \\ \\ volume \: of \: the \: small \: ball \: = \frac{1}{3} \pi {r}^{3} \\ \\ = \frac{1}{3} \times \frac{22}{7} \times {1}^{3} \\ \\ = \frac{1}{3} \times \frac{22}{7} \times 1 \times 1 \times 1 \\ \\ = \frac{22}{21} {cm}^{3} \\ \\ hence \: number \: of \: balls \: can \: be \: made \: \\ from \: the \: the \: larger \: spherical \: ball \\ \\ = \frac{volume \: of \: larger \: spherial \: ball \: }{volume \: of \: small \: ball} \\ \\ = \frac{12672}{7} \times \frac{21}{22} \\ \\ = 576 \times 3 \\ \\ = 1728 \\ \\ 1728 \: small \: balls \: can \: be \: made. \\ \\ hope \: this \: helps \: u...$


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