A solid sphere of mass M and radius R having
moment of inertia l about its diameter is recast into
solid disc of radius r and thickness t. The moment
of inertia of disc about edge and perpendicular to
plane is I, then
(1)r=2R√15
(2) r = R/√15
(3) r=R/4
(4)r =R/√4
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Answer:
r = 2R/√15
Explanation:
2/5 MR² = 3/2 Mr²
r = 2R/√15
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