A solid sphere of mass m is lying at rest on a rough horizontal surface. The coefficient of friction between the ground and sphere is μ. The maximum value of F, so that the sphere will not slip, is equal to______
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Answer:
f≤μmg⇒F=72umg
EXPLANATION
P
FR = IPa
⇒FR=(75MR2)α
⇒Rα=5F7M=a
F−f=Ma⇒f=27F
f≤μmg⇒F=72umg
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