Physics, asked by swastiibarjatya9397, 10 months ago

A solid sphere of mass M, radius R and having moment of inertia about as axis passing through the centre of mass as I, is recast into a disc of thickness t, whose moment of inertia about an axis passing through its edge and perpendicular to its plance remains I. Then, radius of the disc will be.

Answers

Answered by Arunavmanna
2

Answer:

Answer -

Length = \frac{L}{4}

4

L

Let the axis at length L/4 be AB.

We know that the moment of inertia of uniform rod with an axis passing through its middle is \frac{ {ML}^{2}}{12}.

12

ML

2

.

So, I_{AB} = I_{CD} + {ML}^{2}I

AB

=I

CD

+ML

2

I_{AB}= \frac{ {ML}^{2}}{12} +\frac{ {ML}^{2}}{16}I

AB

=

12

ML

2

+

16

ML

2

I_{AB}= \frac { {4ML}^{2} + {3ML}^{2}}{48}I

AB

=

48

4ML

2

+3ML

2

\boxed {I_{AB}= \frac {{7ML}^{2}}{48}}

I

AB

=

48

7ML

2

Explanation:

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