Question

A solid sphere of radius 1cm is carrying a charge of 2 c.find the electric field intensity at the center,on its surface and at point 2 cm from the centre of the charged sphere​

Answer 1

Answer:

your size 15 to 1 centimetre can charge of the Fear Files electricity find interest to centre on its surface and point to son from centre of change fight

Answer 2

Answer:

A sphere of radius 1cm has an electric charge of 2C

1. the electric field at a distance of 2cm from the center is $45*10^{12} N/C$
2. the electric field on the surface is $18*10^{13} N/C$
3. the electric field at the center $E=0$

Explanation:

• The electric field is the electrostatic force between a charge and a unit test charge

• The electric field due to a solid sphere with surface charge $q$ and radius $R$ at a distance $r$ from the center of the sphere (outside), is given by the Gauss law as

                        $E_{out} =\frac{q}{4\pi \varepsilon _0r^{2} }$

• The electric field on the surface  ($r=R$)

                     $E_{on} =\frac{q}{4\pi \varepsilon _0R^{2} }$

• The electric field inside the sphere at a distance x from the center is

                    $E_{in} =\frac{qx}{4\pi \varepsilon _0R^{3} }$

  where the value of  $\frac{1}{4\pi \varepsilon _0} =9*10^{9}$

• electric field does not depend on the dimension of the sphere

From the question, we have

The surface charge of the sphere $q=2C$

the distance where we want to find the field is $r=2cm=0.02m$

⇒the outside electric field is

$E_{out} =\frac{9*10^{9}*2 }{(0.02)^{2} } =45*10^{12} N/C$

the radius of the sphere $R=1cm=0.01m$

electric field on the surface is $E_{on} =\frac{9*10^{9}*2}{(0.01)^{2} } =18*10^{13} N/C$

at the center of the sphere  $x=0$

the corresponding electric field at the center  $E_{center}=0$