A solid sphere of radius 3 cm is melted and then recast into small spherical balls each of diameter 0.6 cm. Find tbe number of balls.
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Let the radius of sphere be R
Let the radius of spherical balls be r
volume of sphere=(volume of spherical balls )n
4÷3πR3=(4÷3πr 3)n
R3=(r3)n
3×3×3=(0.3×0.3×0.3)n
27. =(0.27)n
n=100
113.14=(11.31)n
samruddhipathak:
the answer for this is wrong
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Let the number of balls be n
Diameter of small spherical balls = 0.6 cm
So, Radius of small spherical balls = 0.6/2 = 0.3 cm
Now, the Radius of solid sphere = 3 cm
Now, the volume of small spherical balls = 4/3πr^3
= 4/3*22/7*0.3*0.3*0.3
Now the volume of solid sphere = 4/3πr^3
=4/3*22/7*3*3*3
We know that the n = volume of solid ball/volume of small ball
Therefore, n = (4/3*22/7*3*3*3) / (4/3*22/7*0.3*0.3*0.3)
n = 3*3*3/0.3*0.3*0.3
n = 27/0.027
n = 1000
Hope the answer is helpful !!
Good Day !!
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