Math, asked by dulapallip1947, 1 year ago

A solid sphere of radius 3cm is melted and recast into small spherical balls each of diameter 0.6cm. Find the number of balls thus obtained.

Answers

Answered by navjotsingh10
4
i hope this helps u plz mark it brainleist
Attachments:

mallikarjunasapthami: Thanks
Answered by lakhwanus009
3

Answer:

100 balls

Step-by-step explanation:

By the way, Before starting answer this question has came in the Pre Board Exams of class 10th today.

Let's Start

We know that Volume of any solid remain same when melted and recasted into any solid.

Therefore,

Area of Big Sphere = Area of small Sphere × Number of Balls

Volume of sphere = \frac{4}{3} \pi r^{3}

Therefore,

Putting values of Given data : \frac{4}{3} \pi r^{3} = \frac{4}{3}\pi r^{3}*n

[Note : Both radius are different, n = number of balls]

\frac{r^{3} }{r^{3} }=n\\ \frac{3*3}{0.3*0.3} =n\\100 = n

So, Now we get our answer i.e 100 balls.

Hope u understand.

Please mark it as the brainliest.



archanajha098: Thanks
Similar questions