Question

a solid sphere of radius 3cm is melted and reformed by stretching it into a cylindrical shaped wire of length 9cm find the radius of wire​

Answer 1

Answer:

answer 2

volume of sphere = 4/3pi r³

= 4/3*3*3*3*pi

=4*9 pi

36 pi

volume of cylinder = pi r²h

pi r² *9

both volumes are same

so,

36pi= pi r²9

36=r² 9

r²=36/9

r=√4

=2

Answer 2

Answer:

$volume \: of \: sphere = volume \: of \: cylinder \\ \frac{4}{3} \pi {r}^{3 } = \pi {r}^{2} h \\ \frac{4}{3} \times {3}^{3} = {r}^{2} \times 9 \\ \frac{4}{3} \times \frac{27}{9} = {r}^{2} \\ 4 = {r}^{2} \\ r = 2 \: cm$