Question

A solid sphere of radius 6 cm is melted into a hollow cylinder uniform thickness of the external radius of the base of the cylinder is 5 cm and its height is 32 cm find the electronic thickness of the cylinder

Answer 1

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Answer 2

Given:-

• Radius of sphere = 6cm
• External Radius of cylinder = 5cm
• Height of the cylinder = 32cm

To find :-

• Find the thickness of the cylinder.?

Solutions:-

• Let the internal Radius of the cylinder be 'r' cm.
• Let the external Radius of the cylinder be 'R' cm.

We know that;

• Volume of sphere = 4/3πr³
• Volume of cylinder = π(R² - r²)

=> 4/3πr³ = π(R² - r²)

=> 4/3 × (6)³ = (5² - r²) (32)

=> 4/3 × 216 = 25 - r² × 32

=> 4 × 72 = 25 - r² × 32

=> 288 = 25 - r² × 32

=> 288/32 = 25 - r²

=> 9 = 25 - r²

=> r² = 25 - 9

=> r² = 16

=> r = √16

=> r = 4cm

• Internal radius = 4cm

So,

• The thickness of the cylinder = (R - r)

=> 5 - 4

=> 1cm

Hence, the thickness of the cylinder is 1cm.