Question

a solid sphere of radius r is melted to recast into  27 solid spheres of radius r find r and ratio of surface areas  of two spheres

Answer 1

4/3/$\pi$$r^{3}$=4/3$\pi$$R^{3}$
$r^{3}$=27$R^{3}$
r=3R
surface area of 1circle/surface area of 2 circle=
$r^{2}$=$R^{2}$
9R*R=R*R
9:1

Answer 2

RADIUS OF 1SPHERE=r
"              "    2SPHERE=R
SO FOR 27 SPHERE=27R
SO r3=27R3
S0 r=3R
NOW SURFACE AREA
4/3 PI r2=4/3 PI R2
9R2=R2
SO THE RATIO IS 9:1