A solid sphere rolls without slipping with velocity v and presses a spring of spring constant k as show in fig. Then the compression in the spring will be :
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A block of mass m=25kg on a smooth horizontal surface with a velocity →v=3ms-1 meets the spring of spring constant k=100N/m fixed at one end as shown in figure. The maximum compression of the spring and velocity of block as it returns to the original position respectively are.
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Explanation:
I of solid sphere is 2/5MR2
So rotational k.e/translational k.e
Is 2/5
So total energy is 7/5 × 1/2mv2
So 7/5 × 1/2mv2 = 1/2Kx2
So x = v✓7m/5k
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