Question

A solid sphere weighs 10N in air , 6N in water and 8N in a liquid. The specific gravity of the liquid is

Answer 1

Explanation:

Weight in a liquid = Actual weight - buoyant force

For Liquid A,

6 = 10 - Buoyant force(A)

Buoyant force(A) = 4N

For Liquid B,

8 = 10 - Buoyant force(B)

Buoyant force(B) = 2 N

Answer 2

The specific gravity of the liquid is 0.195.

Explanation:

Given that,

Weight of solid sphere in air = 10 N

Weight of solid sphere in water = 6 N

Weight of solid sphere in liquid = 8 N

Suppose the radius of solid sphere is 10 cm.

We need to calculate the specific gravity

Using formula of specific gravity

$\text{specific gravity}=\dfrac{\rho_{object}}{\rho_{water}}$

$\text{specific gravity}=\dfrac{\dfrac{M_{object}}{V}}{\rho_{water}}$

We need to calculate the specific gravity of the liquid

$\text{specific gravity}=\dfrac{\dfrac{M_{l}}{\dfrac{4}{3}\pi\timesr^3}}{\rho_{w}}$

Put the value into the formula

$\text{specific gravity}=\dfrac{\dfrac{8}{9.8\times\dfrac{4}{3}\pi\times(10\times10^{-2})^3}}{1000}$

$\text{specific gravity}=0.195$

Hence, The specific gravity of the liquid is 0.195.

Learn more :

Topic : specific gravity

https://brainly.in/question/1524875