Question

A solid spherical ball of the metal divided into two hemisphere and joined as shown in the figure. The solid is placed in a cylindrical tub full of water in such a way that the whole solid is submerged in water. The radius and height of cylindrical tub are 4 cm ad 11 cm respectively and the radius of spherical ball is 3 cm Find the volume of water left in the cylindrical tub​

Answer 1

Answer:

4/3πr3 = 12π cm3(vol.of 2 hemispheres)

πr2h=176π cm3(vol. of cylinder)

vol. displaced = vol. of 2 hemisphere

=> vol.of water remaining is

vol.of cylinder-vol. of 2 hemisphere

= 176π-12π

=154π = 484 cm3

ans: the remaining vol. of water in the cylinder is 484 cm3