Question

A solid spherical conductor of radius R has spherical cavity of radius a (a is smaller thn R) .At its centre .The charge at the inner surface ,outer surface are at position r (a is smaller thn r and r is smaller thn R) are respectively.Find the charge at position r and R​

Answer 1

Answer:

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Answer 2

Whether inner surface of the tube be S1 and the outer surface be S2 and the charge be Q.

Then Ea will be given as $\frac{K G}{r_{a}^{2}}$

While that on surface S1 and S2 would be zero .When comes to Eb it will be $\frac{K G}{r_{b}^{2}}$ for Q and for or S1 $\frac{K(-G)}{r_{b}^{2}}$ well for S2 it will be zero. The value for Ec for all three will be $\frac{K G}{r_{C}^{2}}, \frac{K(-G)}{r_{C}^{2}}, \frac{K(2 G)}{r_{C}^{2}}$ respectively