A solid Square of Side 50 cm and Thickness 10cm is in contact with Steam at 1000C on one side. A block of ice at 00C rests on the other side of the solid 5 kg of ice is melted in one hour. Calculated the Thermal conductivity of the solid. Given specific latent heat of ice = 3.36x105 Kg-1k-1.
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1
Answer:
Correct option is
B
1.24J/m/s/
o
C
From Fourier's law we have,
dt
dQ
=
L
KA
(T
1
−T
2
)
Q=
L
KA
(T
1
−T
2
)t
Q=mL
f
L
KA
(T
1
−T
2
)t=mL
f
K=
A(T
1
−T
2
)t
mL
f
(L)
K=
0.36×100×3600
4.8×3.36×10
5
×0.1
J/m/s/
o
C
K=
0.36×36
4.8×3.36
K=1.24J/m/s/
o
C
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Solution To Question ID 306749
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