A solid toy is in the form of a hemisphere surmounted by a right circular
cone of same radius. The height of the cone is 10 cm and the radius of the
base is 7 cm. Determine the volume of the toy. Also find the area of the
coloured sheet required to cover the toy. (Use π = 22/7 and √149 = 12.2)
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Answer:volume=1232cm3
Csa=576.4cm2
Step-by-step explanation:
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Step-by-step explanation:
Given A solid toy is in the form of a hemisphere surmounted by a right circular cone of same radius. The height of the cone is 10 cm and the radius of the base is 7 cm. Determine the volume of the toy. Also find the area of the coloured sheet required to cover the toy. (Use π = 22/7 and √149 = 12.2)
- Given height of cone = h = 10 cm
- Radius of base r = 7 cm
- Volume of cone V1 = 1/3 π r^2 h
- = 1/3 π x 49 x 10
- = 490 π / 3
- Volume of hemisphere V2 = 2/3 π r^3
- = 2/3 π x 7 x 7 x 7
- = 686 π / 3
- So V1 + V2 = 490 π / 3 + 686 π / 3
- = 1176 π / 3
- = 1232 cm^3
- We know that curved surface area of cone = π r l
- = 22/7 x 7 x 12.2 (l = √r^2 + h^2 = √7^2 + 10^2 = √149)
- = 268.4
- Curved surface area of hemisphere = 2 π r^2
- = 2 x 22/7 x 7 x 7
- = 44 x 7
- = 308
- So total area to cover the sheet will be 268.4 + 308 = 576.4 cm^2
Reference link will be
https://brainly.in/question/15921502
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