a solid toy is in the form of a hemisphere surmounted by a right circular cone of same radius. The height of the cone is 10 cm and the radius of the base is 7 cm. Determine the volume of the toy. Also find the area of the coloured sheet required to cover the toy. (Use pi=22/7 and root 149=12.2)
Answers
★ To find:-
- Volume of toy = Volume of cone + Volume of hemisphere
★ Given:-
- Radius = 7cm
- Height of cone = 10cm
★ Volume of the cone = ⅓πr²h
⅓ x 22/7 x 7 x 7 x 10
1540 / 3 cm³
★ Volume of hemisphere = ⅔ πr³
⅔ x 22 / 7 x 7 x 7 x 7
2156 / 3 cm³
★ Volume of the toy = 2156/3 + 1540/3
3696 / 3
l² = r² + h²
(7)² + (10)²
49 + 100
l = √149
Area of coloured paper required = C.S.A of cone + C.S.A of hemisphere
★ C.S.A of cone = πrl
22 / 7 x 7 x 12.2
★ C.S.A of hemispher = 2πr²
2 x 22 / 7 x 7 x 7
★ Area of required paper:-
268.4 + 308
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Given:
The height of the cone is (h) = 10cm
The radius of the base is (r) = 7cm
To Find:
The volume of the toy and the area of the coloured sheet required to cover the toy.
Solution:
We know that the volume of the cone of height h and radius r is given by
V = (1/3)Пr²h
Putting the respective values, we get,
V = (1/3)П(7)²(10) cm³
= 490П/3 cm³
The volume of the hemisphere of radius
7cm is given by
V' = (2/3)Пr³
= (2/3)П(7)³
= 686П/3 cm³
Total volume = V + V'
= (490П/3 + 686П/3) cm³
= 392П cm³
= (392*22/7) cm³
= 1232 cm³
Let the slant height be l cm
l = √(r²+h²)
= √(7²+10²)
= 12.2cm
So, curved surface area of the cone Пrl
Putting the respective values, we get
Curved Surface Area= П(7)(12.2) cm²
= 85.4П cm²
Curved Surface Area of hemisphere = 2Пr² cm²
= 2П(7)² cm²
= 98П cm²
Total area = (85.4+98)П cm²
= 183.4П cm²
= (183.4*22/7) cm²
= 576.4 cm²
Therefore, the area of the coloured sheet required to cover the toy is 576.4 cm².