Question

A solid toy is in the form of a hemisphere surmounted by a right circular cone. The height of the cone is 2 cm and the diameter of the base is 4 cm. Determine the volume of the toy. If a right circular cylinder circumscribes the toy, find the difference between the volumes of the cylinder and the toy. (Take π = 3.14)​

Answer 1

Answer:

Volume of toy = Vol. of cone + Vol.of hemisphere

$= \frac{1}{3} \pi \: {r}^{2} h + \frac{2}{3} \pi \: {r}^{3}$

$= \frac{1}{3} \pi \: {r}^{2} (h + 2r)h$

$= \frac{1}{3} \times \frac{22}{7} \times 2 \times 2(2 + 2 \times 2)$

$= 25.12 \: {cm}^{2}$

Vol. of cylinder =

$\pi \: {r}^{2} h \: = \frac{22}{7} \times 2 \times 2(2 + 2) = 50.24 \: {cm}^{2}$

Difference in volume =50.24−25.12=25.12cm3

Hence, cylinder cover 25.12cm3 more space.

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Answer 2

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✒️Your Question :-

➡ A solid toy is in the form of a hemisphere surmounted by a right circular cone. The height of the cone is 2 cm and the diameter of the base is 4 cm. Determine the volume of the toy. If a right circular cylinder circumscribes the toy, find the difference between the volumes of the cylinder and the toy. (Take π = 3.14)

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✒️Answer :-

Volume of toy is 25.12 centimeter cube.

The difference of the volume of cylinder and toy is 25.12 centimeter cube.

Given : A solid toy is in the form of a hemisphere surmounted by a right circular cone. The height of the cone is 2cm and the diameter of the base is 4cm.

To find : Determine the volume of the toy. If a right circular cylinder circumscribes the toy, find the difference of the volume of cylinder and toy.

Solution :

Height of the cone is h=2 cm

Diameter d= 4 cm

Radius r=2 cm

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➡️ hope this helps you ❗️❗️

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