Question

A solid toy is in the form of a hemisphere surmounted by a right circular cone. The height of the cone is 2cm and the diameter of the base is 4cm. Determine the volume of the toy. If a right circular cylinder circumscribes the toy, find the difference of the volume of cylinder and toy. Take pie=3.14

Answer 1

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differences of the volumes of the cylinder and the toy is 25.12 cm^2
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Answer 2

Answer:

Volume of toy is 25.12 centimeter cube.

The difference of the volume of cylinder and toy is 25.12 centimeter cube.

Step-by-step explanation:

Given : A solid toy is in the form of a hemisphere surmounted by a right circular cone. The height of the cone is 2cm and the diameter of the base is 4cm.

To find : Determine the volume of the toy. If a right circular cylinder circumscribes the toy, find the difference of the volume of cylinder and toy.

Solution :

Height of the cone is h=2 cm

Diameter d= 4 cm

Radius r=2 cm

Volume of the toy is $V=\frac{1}{3}\pi r^2(2r+h)$

$V=\frac{1}{3}(3.14) 2^2(2(2)+2)$

$V=\frac{1}{3}(3.14)(4)(6)$

$V=(3.14)(4)(2)$

$V=25.12cm^3$

Volume of the cylinder $v=\pi r^2 h$

$v=(3.14)(2)^2(2)$

$v=(3.14)(4)(2)$

$v=50.24 cm^3$

The difference of the volume of cylinder and toy is

$v-V=50.24-25.12$

$v-V=25.12cm^3$