a solid toy is in the form of a hemisphere surrounded by a right circular cylinder the height of the cone is 6cm and diameter of the base is 8cm
a. find the value of a toy
b. find the total surface area of the toy
c. find the difference of the valumes of cone and hemisphere
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Volume of toy = Vol. of cone + Vol.of hemisphere
=
3
1
πr
2
H+
3
2
πr
3
=
3
1
πr
2
[H+2r]h
=
3
1
×
7
22
×2×2[2+2×2]
=
3
1
×
7
22
×4×6
2
=25.12cm
3
Volume of cylinder =πr
2
h=
7
22
×2×2[2+2]=
7
22
×16=50.24cm
3
Difference in volume =50.24−25.12=25.12cm
3
Hence, cylinder cover 25.12cm
3
more space.
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