A solid toy is in the form of hemisphere surmounted by a right circular cone. The height of cone is 4cm and diameter of base is 8cm . Determine the volume of toy .If a cube circumscribes the toy, then find difference of
Volumes of cube and toy
Answers
Answer:
Step-by-step explanation:
Radius of the hemisphere and the cone = 4 cm
Height of the cone = 4 cm
Volume of the toy = volume of the hemisphere + volume of the cone
A cube circumscribes the given solid. Therefore, edge of the cube should be 8 cm.
Volume of the cube = 83 = 512 cm3
Difference in the volumes of the cube and the toy = 512 - = 310.86 cm3
Total surface area of the toy = curved surface area of cone + curved surface area of hemisphere
= rl + 2r2, where l = == 4
= r (l + 2r)
= 4 (4 + 2 4)
=fraction numerator 88 cross times 4 left parenthesis square root of 2 plus 8 right parenthesis over denominator 7 end fraction
= 171.68 cm2
Answer:
Radius of the hemisphere and the cone = 4 cm
Height of the cone = 4 cm
Volume of the toy = volume of the hemisphere + volume of the cone
A cube circumscribes the given solid. Therefore, edge of the cube should be 8 cm.
Volume of the cube = 83 = 512 cm3
Difference in the volumes of the cube and the toy = 512 - = 310.86 cm3
Total surface area of the toy = curved surface area of cone + curved surface area of hemisphere
= rl + 2r2, where l = == 4
= r (l + 2r)
= 4 (4 + 2 4)
=fraction numerator 88 cross times 4 left parenthesis square root of 2 plus 8 right parenthesis over denominator 7 end fraction
= 171.68 cm2
Step-by-step explanation: