a solid trophy weighs 200 n in air and 160 n in water. what is its density
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Answered by
2
difference of weight= 200-160 = 40
taking the ratio= pt/pa= 200/40
pt/pa= 5
pt = 5 x pa
pt= 5 x 5 kg/m3
taking the ratio= pt/pa= 200/40
pt/pa= 5
pt = 5 x pa
pt= 5 x 5 kg/m3
Answered by
56
Explanation:
difference of weight= 200-160 = 40
taking the ratio= pt/pa= 200/40
pt/pa= 5
pt = 5 x pa
pt= 5 x 5 kg/m3
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