Question

a solid weighing 1000 N exerts a pressure of 10⁵ Pa when placed on table calculate the area of contact with the table top​

Answer 1

Provided that:

• Weight = Force = 1000 = 10³ N
• Pressure = 10000 = 10⁵ Pa

To calculate:

• Area of contact

Solution:

• Area of contact = 10-² = 0.01 m

Using concept:

• Pressure formula

Using formula:

• Pressure = Force/Area

Required solution:

↦ Pressure = Force/Area

↦ P = F/A

↦ 10⁵ = 10³/A

↦ A = 10³/10⁵

↦ 10^3-5 m = A

↦ 10-² m = A

↦ Area of contact = 10-² m

↦ Area of contact = 0.01 m

• Henceforth, area of contact = 10-² metres or 0.01 metres.

Additional information:

$\begin{gathered}\boxed{\begin{array}{c}\\ {\pmb{\sf{Some \: formulas!}}} \\ \\ \sf \star \: Pressure \: = \dfrac{Force}{Area} \\ \\ \sf \star \: Area \: = \dfrac{Force}{Pressure} \\ \\ \sf \star \: Pressure \times Area = Force \end{array}}\end{gathered}$

Answer 2

Given:

A solid weighing 1000 N exerts a pressure of 10⁵ Pa when placed on table.

To find:

Area of contact?

Calculation:

• Pressure is a scalar quantity and is defined as the ratio of perpendicular force (or thrust) and surface area of contact.

$P = \dfrac{F}{area}$

$\implies \: area = \dfrac{F}{P}$

$\implies \: area = \dfrac{1000}{ {10}^{5} }$

$\implies \: area = {10}^{ - 2} \: {m}^{2}$

$\implies \: area = 0.01\: {m}^{2}$

So, area of contact is 0.01 m².