Question

A solid weighing 277.5 gm in airand 212.5gm is totally immersed in the liquid density of 0.9 gm/cm^3. Calculate the density of the solid. plz give the answer with full process

Answer 1

Answer:

Hey check your question density is given we should find the area.

The solid apparently weighs less in water when compared to air because of the upward buoyant force acting on it when it is submerged in water.

According to Archimedes principle, the buoyant force acting on an object is equal to the weight of the fluid displaced by it.

Therefore, the apparent decrease in the weight of an object is equal to the weight of the fluid displaced by it.

Weight of displaced water = Apparent decrease in weight = 277.5-212.5 = 65gm

Given, density immersed in liquid is 0.9gm/cm^3

We know that Area = Mass / density

= 65 / 0.9

= 72.2cm^3

Density = Mass / Area

= 65 / 72.2 = 0.9gm/cm^3.