Question

A solid weighs 1.5 kgf in air and 0.9 kgf in a liquid of density 1.2 x 103 kg m^-3. Calculate R.D. of solid.​

Answer 1

Answer:

The answer is 3.

Hope it helps you

Answer 2

Answer:

i hope it hlp u

Explanation:

weight of body in air, W1= 1.5KGF

weight of body when completely immersed in liquid W2 =0.9kgf

density of liquid =1.2*10^3 kgm^-3

R.D of body = W1/W1-W2. * RD of liquids

RD of body = 1.5/1.5*0.9*1.2

RD of body =3