Question

A solid weighs 1.5kgf in air and 0.9 kgf in a liquid of density 1.2×10^3 kg m^-3.Calculate R.D of solid.​

Answer 1

Step-by-step explanation:

It is simple to find it by using the formula for the relative density of solid.

$\begin{gathered}r.d._{solid}=\frac{W_{air}}{W_{air}-W_{liquid}}*\frac{d_{liquid}}{d_{water}}\\\\=\frac{1.5}{1.5-0.9}*\frac{1.2*10^3}{1*10^3}=3.0\end{gathered}$

r.d.

solid

=

W air −W liquid

W air

∗ d water d liquid

= 1.5−0.1 1.5

∗ 1∗10 3

1.2∗10 3

=3.0

so 3.0 is the answer.