Question

a solid weighs 120 GF in air and 105 GF when it is completely immersed in water calculate the relative density of solid​

Answer 1

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Given, weight of solid in air W1 = 50 gf and weight of solid in water w2 = 44 gf

(i) Upthurst = loss in weight when immersed in water = W1 - W2 = 50 - 44 = 6 gf

(ii) Weight of water displaced = upthurst = 6 gf

Since density of water is 1 g/m³, therefore volume of water displaced = 6cm³

But the solid displaces water equal to its own volume, therefore volume of solid = 6cm³.

(iii) R.D. of solid = Weight of solid in air / Weight in air - Weight in water

= W1 / W1 - W2 = 50 / 50 - 44 = 50 / 6 = 8.33

Answer 2

Answer:

A solid weighs 120 gf in air & 105 gfwhen it is completely immersed in water . calculate the relative density of solid - 727221. ... so the relative density of the solid is 8. cliffffy4h and

Explanation:

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