Question

A solid weighs 120 gf in air and and 105 gf when it is
completely immersed in water. Calculate the relative
density of solid.
Ans.
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Answer 1

Answer:

105+120=225gf

Step-by-step explanation:

u should add the no. given

Answer 2

Given

• Weight of solid in air = 120 gf
• Weight of solid when it is completely submerged in water = 105 gf

To find

• Relative density of solid

Solution

Using formula,

$\large \underline{\boxed{ \sf{relative \: density \: of \: solid \: = \dfrac{weight \: of \: solid \: in \: air}{weight \: of \: solid \: in \: air \: - weight \: of \: solid \: in \: water}}}} \purple \bigstar$

Substituting the given values,

$\quad \sf \implies \dfrac{120}{120 - 105} \\ \\ \\ \quad \sf \implies \dfrac{120}{15} \\ \\ \\ \quad \sf \implies 8 \\ \\ \\ \therefore \boxed{ \sf {relative \: density \: of \: solid = 8}}$

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Know MorE

• Relative density is the ratio between density of a substance and density of water at 4°C.
• It does not have any unit.
• The numerical value of density and relative density is same in CGS system.
• Density in S.I. system = R.D. × 1000 $\sf{kg/m^3}$
• Density in CGS system = R.D. × 1 $\sf{g/cm^3}$