Physics, asked by anshruta2007, 1 month ago

A solid weighs 140 gf in air and 132 gf when completely immersed in water.

Find: i) the volume of solid

ii) R.D. of solid

iii) volume of solid

Answers

Answered by dhirajchoudhary2100
11

Answer:

when compared to air because of the upward buoyant force acting on it when it is submerged in water.

According to Archimedes principle, the buoyant force acting on an object is equal to the weight of the fluid displaced by it.

Therefore, the apparent decrease in the weight of an object is equal to the weight of the fluid displaced by it.

Weight of displaced water = Apparent decrease in weight = 120−105=15 gf

Mass of displaced water = 15g

Volume of solid = volume of water displaced =

density

mass

=

1g/cm

3

15g

=15cm

3

Actual weight of solid = weight of solid in air =120gf (since buoyant force due to air is negligible)

Mass of solid = 120g

Density of solid =

Volume

Mass

=

15

120

=8g/cm

3

Relative density of solid =

Density

water

Density

solid

=

1g/cm

3

8g/cm

3

=8

Explanation:

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