Question

a solid weighs 30 N ehen dipped in water and weighs 40 N in air. the density of the solid is​

Answer 1

Answer:

When the weight is submerged and not accelerating, the forces up equal the forces down.

Fup =Fdn

30N + Fb = 40N

Fb = 10N

Fb = the weight of water displaced by the object.

10N of water is displaced. Weight =m*g if we let g=10m/s/s, then the mass of the water displaced is 1 kg.

Water has a density of 1kg/liter, so the volume of the water displaced is 1 liter. The volume of the water displaced equals the volume of the object.

The object’s m = w/g =40/10= 4kg

so the object’s density is 4kg/1 liter.

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Explanation:

Answer 2

Answer:

4kg m^-3

Explanation:

Using formula W1/W1-W2

40N/40N-30N

=40/10

=4N