Question

a solid weighs 32 gf in air,and 28.8 gf in water.find the volume and density of the solid.find how much will it weigh in a liquid of density 0.9 g/cm^3

Answer 1

Let V be the volume of the solid.Given relative density of the liquid =0.8Weight of the solid in air = 30 gfWeigth of the solid in liquid = 26 gfWe know that the loss in weight of the solid when immersed in liquid = The weight of the liquid displaced.  ----------(1)Weight of the liquid displaced = Volume of the liquid displaced × Relative density of the liquid  = V × 0.8   -----------------------(2)(2) in (1) gives:Loss in weight of the solid when immersed in liquid = 0.8 V  ----(3)Loss in weight of the solid when immersed in liquid = (30 -26)gf = 4 gf   Substituting in (3) we get:4 = 0.8 Vi.e V =4 /0.8 = 5 cm3(1) Therefore the volume of the solid  = 5 cm3Density of the solid = Mass / volume = 30 gf / 5 cm3 =6 g/cm3(2) Relative density of the solid =Density of the solid / Density of water = (6 g /cm3) /(1 g /cm3) = 6 g/cm3Relative density of the solid = 6 g/cm3

Answer 2

Answer:

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