Math, asked by saniaashif55555, 7 months ago

A solid weighs 32 gf in air and 28.8of in water . Find: (i) the volume of solid (ii) R.D. of soild and (iii) the weight of soild in a liquid of density 0.9g cm^-3​

Answers

Answered by vy6771805
4

Answer:

A solid weights 32f in air.

and in water 28.8gf.

Step-by-step explanation:

1 = Weight of solid in air,W1 =32 gf

Weight of solid when completely immersed in water ,W2

(1) Volume of solid =Mass/density of solid

32/10=3.2m³

(2) R.D. of solid —W1/W¹—W² × R.D. of water R.D. of solid

=32/32=28.8 ×1

(3)=weight of solid in liquid of dinesity 0.9gcm=W³R.D. of solid =

W¹/W¹—W³×R.D. of liquid

or,10=32/32—W³×0.9

or,W³=29.12gf

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