Question

A solid weighs 600 g in air, 450 g in water and 480 g in a liquid. Find :
(i) volume of the solid,
(ii) R.D. of the solid, and
(iii) R.D. of the liquid

Answer 1

volume of solid = 150 cm3

RD of the solid = 4

RD of the liquid = 0.8

Explanation:

Weight of water displaced = 600 - 450 = 150 g.  

Density of water = 1 g/cm3

Density = mass / volume

So volume of solid = mass / density = 150 /1 = 150 cm3

RD of the solid = Weight in air / (Weight in air - Weight in water)

= 600/ (600 - 450)  

= 600/150  

= 4

RD of the liquid = Loss of weight of solid in liquid / Loss of weight of solid in water

= (600 - 480) / (600 - 450)  

= 120 / 150  

= 0.8