Question

A solid weighs 80g in air ,68g in water and 60g in oil.Calculate the relative density of the solid to the oil

Answer 1

weight of solid in air =80g

weight of solid in water =68g

weight of solid in oil=60g

relative density=loss of weight of solid in air/loss of weight of solid in water

relative density=80-60/80-68

=20/12=5/3=1.67

Answer 2

Given :

Weight of solid in air , $W_a=80\ g$ .

Weight of solid in water , $W_b=68\ g$ .

Weight of solid in oil , $W_o=60\ g$ .

To Find :

The relative density of the solid to the oil .

Solution :

Relative density is given by :

$R.D=\dfrac{\text{Loss of weight in air }}{\text{Loss of wight in water }}$

$R.D=\dfrac{W_a-W_o}{W_a-W_w}$

Putting all values in above equation .

We get :

$R.D=\dfrac{80-60}{80-68}\\\\R.D=1.67$

Therefore , the relative density of the solid to the oil 1.67 .

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Relative Density

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