Question

A solid weight 32gf in air and 28.8gf in water. Find the volume and RD of the solid. Find how much it will weigh in a liquid of density 0.9 g/cm³.

please give the answer with process in a paper


irrelevant answers will be reported


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Answer 1

Answer:

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${\huge{\tt{\boxed{\fcolorbox{red}{black}{Solution:-}}}}}$

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Given,

Weight of solid in air, W, 32 gf

Weight of solid when completely immersed in water W2 = 28.8 gf

(i) Volume of solid = Mass / density of solid.

$= \frac{32}{10} = 3.2 {m}^{2}$

(ii) R.D. of solid =

$\frac{w1}{w1 - w2} \times r.d \: \: of \: \: water. \\ \\ \\ r.d \: \: of \: \: solid \: = \: \frac{32}{32 - 28.8} \times 1$

So, R.D of water = 10.

Hence Solved!

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Hope it helps you dear!

Answer 2

Refer the attachment friend ↗️↗️↗️↗️