Question

a solid weights 0.9n in air and 0.2n in a liquid of density 700kg/m. calculate the upthrust and volume of the solid 10cm​

Answer 1

Answer:

Correct option is

D

2cm3

Given,

Weight of the object in air =0.1N

Weight of the object in water =0.08N

The volume of the object (V)=?

The reduction in weight is due to buoyant force (FB). 

∴ Buoyant force (0.1−0.08)=0.02N

From Archemede's principle,

FB=Weight of the displaced water = Volume of water displaced× Density of water×g

⇒0.02=V×103×10

⇒V=1040.02m3=0.02×104106cm3=2cm3

Explanation:

⇒0.02=V×103×10

⇒V=1040.02m3=0.02×104106cm3=2cm3