Question

A solid wooden cone of diameter 14 cm and vertical height 24 cm is vertically cut into two equal halves.Find Total surface area of one half.​

Answer 1

Solution

d=14 cm

r=7cm

h=24cm

therefore..

lateral height (l)=√(7²+24²)=25 cm

now the cone is cutted into two pieces vertically..so now each of will contain curved surface portion and a triangular plane portion..

•area of the curved portion

=πrl/2

$= ( \frac{22}{7} \times 7 \times 25)cm {}^{2} \\ = 550 \: cm {}^{2}$

and the area of the triangular portion of sides d=14cm,l=25cm and again l=25cm

$= \sqrt{32(32 - 24)(32 - 25) {}^{2} } \\ = \sqrt{32 \times 8 \times 7 {}^{2}} \\ = 7 \times 8 \times 2 \\ = 112 \: cm {}^{2}$

therefore total surface area

=(550+112)Cm²

=662cm²

Hope this helps you....