Question

A solid wooden toy is in the form of a hemisphere surmounted by a cone of same radius. The radius of hemisphere is 3.5cm and the total wood used in the making of toy is 166 5/6 cm³. Find the height of the toy. Also, find the cost of painting the hemispherical part of the toy at the rate of Rs. 10 per cm² (Take π=22/7)

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Answer 1

$quesion$

A solid wooden toy is in the form of a hemisphere surmounted by a cone of same radius. The radius of hemisphere is 3.5cm and the total wood used in the making of toy is 166 5/6 cm³. Find the height of the toy. Also, find the cost of painting the hemispherical part of the toy at the rate of Rs. 10 per cm² (Take π=22/7)?

$given$

• The radius of hemisphere is 3.5cm 

• total wood used in the making of toy is 166 5/6 cm³.
• (Take π=22/7)

$SOLUTION$

.r = radius of hemisphere .

.cone = 3.5 cm ; h = height of cone.

Volume

$v \: total \: = v \: cone \: + hemisphare \: = 1 \: \div 3 \pi \: r {?}^{2} + 2 \div 3\pi \: r {?}^{2}$

=166•83 cm^2.

==>πr^2(h+2r)=500•5cm^2.

==>h+2(3•5)=500•5

••••••••••

π*3•5^2

hence==>.h=13-7=6cm.

height of. toy.

=h+r=6+3•5=9•5cm.

Surface area of hemisphere

=2π(3•5)^2=77cm^2.

$cost \: = r \: 770answer$

hence. proved.

hope. it's. helps. you ✔️

Answer 2

Answer:

here is your answer mate....

Step-by-step explanation:

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