Question

A solid XY kept in an evacuated sealed container undergoes
decomposition to form a mixture of gases X and Y
temperature T. The equilibrium pressure is 10 bar in this
vessel. K, for this reaction is
(1) 25 (2) 100 (3) 10 (4)05​

Answer 1

(1) 25 is correct answer

Explanation:

The chemical equation is given below:

$\ce{ XY(s) <=> X(g) + Y(g)}$

At equation,

Total pressure $= 2P =10 \; bar$

$P=5$

$K_p = (P_x)(P_y) = P^2 = 5^2 =25$

Thus, value of K is 25

Answer 2

Equilibrium constant K for this reaction is 25

Explanation:

Equilibrium constant is the ratio of the concentration of products to the concentration of reactants each term raised to its stochiometric coefficients.

The balanced chemical reaction is:

                              $XY(s)\rightleftharpoons X(g)+Y(g)$                                

Initial pressure       0                 0     0

At eqm.                                      x      x

x + x = 10 bar

2x = 10

x = 5 bar

$K_p={p_X\times p_Y}$

$K_p=5\times 5=25$

The equilibrium constant K for this reaction is 25

Learn more about Equilibrium constant  

https://brainly.com/question/11495410

https://brainly.com/question/8606358