A soln containng 10 g of non volatile solute in 100 g of water boils at 373.15 k find molecular mass of solute
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Δtb = kb molality
373.15-300 =0.51x 10/x *1000/100
molecular mass = 0.51 x10x100/0.15
=100x0.51/0.15 = 340 gm
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