Question

A soln of 50ml 0.5m NaOH is added to 150ml 0.10M HNO₃. Find pH of resulting soln.​

Answer 1

Answer:

no. of moles=volume×molarity

no.moles of naoh=50×0.5=25mole

no.of moles of hno3=150×0.1=15 mole

when 1 mole of naoh added to 1 mole of hno3

resulting solution has ph equal to 7

but when 15 mole of hno3 added to 25 mole of naoh

only 15 moles of both react forms neutral solution

as 10 mole of naoh remains

concentration of oh-=10/200=0.05

poh=2-log5

ph=14-poh

ph=14-2+log5

ph=12+0.6989

ph=12.6989