Question

A solution 500ml of acetone in water contain 250g of acetone in water. Then the concentration of acetone solution is​

Answer 1

This solution contains of this liquid solute (alcohol) mixed with a liquid solvent (water) ,so we have to calculate the concentration of this solution in terms of volume percentage of solute (alcohol ) .(Now, we know that :

Conentration of solution =Volume of soluteVolume of solution ×100

Here ,Volume of solute (alcohol ) =50mL

ANd , Volume of solvent (water ) =150mL

SO , VOlume of solution = Volume Of solute + Volume of Solvent

=50+150

=200mL

Now ,putting these values of volume fo solute and volume of solution in the the above formula we get :

Concentration of sodium =50200×100

=502

=25 per cent (by volume )

thus , the concentration of this alcohol solution is 25 per cent or that it is a 25% alcohol solution (by volume ).

Answer 2

This solution contains of this liquid solute (alcohol) mixed with a liquid solvent (water) ,so we have to calculate the concentration of this solution in terms of volume percentage of solute (alcohol ) .(Now, we know that :

Conentration of solution =Volume of soluteVolume of solution ×100

Here ,Volume of solute (alcohol ) =50mL

ANd , Volume of solvent (water ) =150mL

SO , VOlume of solution = Volume Of solute + Volume of Solvent

=50+150

=200mL

Now ,putting these values of volume fo solute and volume of solution in the the above formula we get :

Concentration of sodium =50200×100

=502

=25 per cent (by volume )