Question

A solution contain 25% water, 25% ethanol and 50% acetic acid by mass. The number of moles of acetic acid (CH3COOH) is​

Answer 1

Explanation:

Hence the mole fraction of water is0.51, ethanoic acid is 0.291 , and ethanol is 0.197.

Answer 2

Answer:

Let the mass of solution is 100g

Then, mass of H2O=25g

      mass of ethanol =25g

mass of acetic acid =50g

Number of moles of water =18g/mol25g=1.4

Number of moles of ethanol =46g/mol25g=0.54

Number of moles of Acetic acid =60g/mol50g=0.8

Total number of moles =(1.4+0.54+0.8)=2.74

Now, mole fraction of water =2.741.4=0.51

         mole fraction of Ethanol =2.740.54=0.197

         mole fraction of acetic acid =2.740.8=0.291

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